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FOXBOROUGH, Mass. – Tom Brady has been named AFC Offensive Player of the Week by the National Football League for his performance in the Patriots’ 45-7 victory over the St. Louis Rams last Sunday in London. It is the 22nd time in his career that Brady has received the AFC Offensive Player of the Week honor, tying Denver’s Peyton Manning for the most Player of the Week awards earned by a player since the accolade was instituted in 1984. It is Brady’s second honor this year, after earning the award for his performance in the Patriots’ 52-28 victory over Buffalo in Week 4.

Brady completed 23 of 35 passes for 304 yards and four touchdown passes against the Rams. It was Brady’s ninth career NFL game with 300 yards, at least four touchdown passes and no interceptions to tie Drew Brees for the all-time lead. After falling behind, 7-0, following the Rams first possession, Brady led the Patriots on six consecutive scoring drives to take a 38-7 lead in the third quarter. It was Brady’s 50th 300-yard game of his career, third among active NFL players, behind Peyton Manning (68) and Drew Brees (62). Brady threw a touchdown pass in his 40th straight game, the third longest streak all-time, behind Brees (50) and Johnny Unitas (47).

It is the third time in 2012 that the patriots have been honored with a Player of the Week Award. Brady was named AFC Offensive Player of the week in Week 4 at Buffalo, and DB Devin McCourty was named AFC Special Teams Player of the Week in Week 7 vs. the New York Jets.