FOXBOROUGH, Mass. – New England Patriots punter Jake Bailey was named AFC Special Teams Player of the Week by the National Football League for his performance in the Patriots 17-10 win on Sunday against the Philadelphia Eagles. It is the second time in 2019 that Bailey has been named AFC Special Teams Player of the Week. He earned the award for the first time in New England's Week 3 victory over the Jets.
Bailey punted eight times for 381 yards for an average of 47.6 yards and landed six punts inside the 20-yard line. Five of his eight punts went for over 50 yards. With the Patriots holding a 17-10 lead late in the game, Bailey launched a 54-yard punt that pinned the Eagles at their own 12-yard line with 34 seconds to play.
Bailey is the first rookie to be awarded two Special Teams Player of the Week honors in the same season since Kansas City Chiefs K Harrison Butker in 2017. Bailey also joins San Francisco 49ers DL Nick Bosa as 2019 rookies to receive multiple NFL honors this season. Bosa has been awarded NFC Defensive Player of the Week twice so far this year.
The Patriots have now earned five NFL honors so far in 2019. In addition to Bailey's two AFC Special Teams Player of the Week honors, LB Kyle Van Noy was named AFC Defensive Player of the Week for Week 4, DB Devin McCourty was named AFC Defensive Player of the Month for September and CB Stephon Gilmore was named AFC Defensive Player of the Month for October.
