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Dion Lewis Named AFC Offensive Player of the Week

FOXBOROUGH, Mass. – Dion Lewis has been named AFC Offensive Player of the Week for his performance in the Patriots 37-16 victory over Buffalo on Sunday. It marks the second time in his career that he has been earned a Player of the Week Award. Lewis was named AFC Special Teams Player of the Week earlier this season after his Week 10 performance in Denver.

Lewis finished the game with a career high 129 yards rushing on 24 attempts and a touchdown and five receptions for 24 yards and a score. Lewis has now totaled 803 rushing yards on 154 attempts with five touchdowns and caught 26 passes for 174 yards and two scores. He is averaging 5.2 yards-per carry this season and if he keeps that pace, he will become the fifth player in team history to finish a season with an average of at least 5 yards per carry (minimum 100 attempts.).

It is the seventh time in 2017 that the Patriots have been honored with a Player of the Week Award. QB Tom Brady was named AFC Offensive Player of the Week in Week 2, 3 and 10. Lewis was named AFC Special Teams Player of the Week in Week 10, K Stephen Gostkowski earned the award after his performance in Week 11 and TE Rob Gronkowski was tabbed AFC Offensive Player of the Week for Week 15. In addition, Brady was named AFC Offensive Player of the Month for November.

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